Optimal. Leaf size=214 \[ a^4 (b B-a C) x+\frac {b \left (32 a^3 b B+16 a b^3 B-24 a^4 C+8 a^2 b^2 C+3 b^4 C\right ) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac {b^2 \left (34 a^2 b B+4 b^3 B-15 a^3 C+12 a b^2 C\right ) \tan (c+d x)}{6 d}+\frac {b^3 \left (32 a b B-6 a^2 C+9 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {b^2 (4 b B+3 a C) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d} \]
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Rubi [A]
time = 0.35, antiderivative size = 214, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 48, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.146, Rules used = {4126, 4003,
4141, 4133, 3855, 3852, 8} \begin {gather*} a^4 x (b B-a C)+\frac {b^3 \left (-6 a^2 C+32 a b B+9 b^2 C\right ) \tan (c+d x) \sec (c+d x)}{24 d}+\frac {b^2 \left (-15 a^3 C+34 a^2 b B+12 a b^2 C+4 b^3 B\right ) \tan (c+d x)}{6 d}+\frac {b \left (-24 a^4 C+32 a^3 b B+8 a^2 b^2 C+16 a b^3 B+3 b^4 C\right ) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac {b^2 (3 a C+4 b B) \tan (c+d x) (a+b \sec (c+d x))^2}{12 d}+\frac {b^2 C \tan (c+d x) (a+b \sec (c+d x))^3}{4 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 3852
Rule 3855
Rule 4003
Rule 4126
Rule 4133
Rule 4141
Rubi steps
\begin {align*} \int (a+b \sec (c+d x))^3 \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx &=\frac {\int (a+b \sec (c+d x))^4 \left (b^2 (b B-a C)+b^3 C \sec (c+d x)\right ) \, dx}{b^2}\\ &=\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {\int (a+b \sec (c+d x))^2 \left (4 a^2 b^2 (b B-a C)+b^3 \left (8 a b B-4 a^2 C+3 b^2 C\right ) \sec (c+d x)+b^4 (4 b B+3 a C) \sec ^2(c+d x)\right ) \, dx}{4 b^2}\\ &=\frac {b^2 (4 b B+3 a C) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {\int (a+b \sec (c+d x)) \left (12 a^3 b^2 (b B-a C)+b^3 \left (36 a^2 b B+8 b^3 B-24 a^3 C+15 a b^2 C\right ) \sec (c+d x)+b^4 \left (32 a b B-6 a^2 C+9 b^2 C\right ) \sec ^2(c+d x)\right ) \, dx}{12 b^2}\\ &=\frac {b^3 \left (32 a b B-6 a^2 C+9 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {b^2 (4 b B+3 a C) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {\int \left (24 a^4 b^2 (b B-a C)+3 b^3 \left (32 a^3 b B+16 a b^3 B-24 a^4 C+8 a^2 b^2 C+3 b^4 C\right ) \sec (c+d x)+4 b^4 \left (34 a^2 b B+4 b^3 B-15 a^3 C+12 a b^2 C\right ) \sec ^2(c+d x)\right ) \, dx}{24 b^2}\\ &=a^4 (b B-a C) x+\frac {b^3 \left (32 a b B-6 a^2 C+9 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {b^2 (4 b B+3 a C) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {1}{6} \left (b^2 \left (34 a^2 b B+4 b^3 B-15 a^3 C+12 a b^2 C\right )\right ) \int \sec ^2(c+d x) \, dx+\frac {1}{8} \left (b \left (32 a^3 b B+16 a b^3 B-24 a^4 C+8 a^2 b^2 C+3 b^4 C\right )\right ) \int \sec (c+d x) \, dx\\ &=a^4 (b B-a C) x+\frac {b \left (32 a^3 b B+16 a b^3 B-24 a^4 C+8 a^2 b^2 C+3 b^4 C\right ) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac {b^3 \left (32 a b B-6 a^2 C+9 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {b^2 (4 b B+3 a C) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}-\frac {\left (b^2 \left (34 a^2 b B+4 b^3 B-15 a^3 C+12 a b^2 C\right )\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{6 d}\\ &=a^4 (b B-a C) x+\frac {b \left (32 a^3 b B+16 a b^3 B-24 a^4 C+8 a^2 b^2 C+3 b^4 C\right ) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac {b^2 \left (34 a^2 b B+4 b^3 B-15 a^3 C+12 a b^2 C\right ) \tan (c+d x)}{6 d}+\frac {b^3 \left (32 a b B-6 a^2 C+9 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {b^2 (4 b B+3 a C) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {b^2 C (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}\\ \end {align*}
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Mathematica [A]
time = 1.34, size = 170, normalized size = 0.79 \begin {gather*} \frac {24 a^4 (b B-a C) d x+3 b \left (32 a^3 b B+16 a b^3 B-24 a^4 C+8 a^2 b^2 C+3 b^4 C\right ) \tanh ^{-1}(\sin (c+d x))+3 b^2 \left (8 \left (6 a^2 b B+b^3 B-2 a^3 C+3 a b^2 C\right )+b \left (16 a b B+8 a^2 C+3 b^2 C\right ) \sec (c+d x)+2 b^3 C \sec ^3(c+d x)\right ) \tan (c+d x)+8 b^4 (b B+3 a C) \tan ^3(c+d x)}{24 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.12, size = 278, normalized size = 1.30 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.31, size = 320, normalized size = 1.50 \begin {gather*} -\frac {48 \, {\left (d x + c\right )} C a^{5} - 48 \, {\left (d x + c\right )} B a^{4} b - 48 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a b^{4} - 16 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B b^{5} + 3 \, C b^{5} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 24 \, C a^{2} b^{3} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 48 \, B a b^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 144 \, C a^{4} b \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) - 192 \, B a^{3} b^{2} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 96 \, C a^{3} b^{2} \tan \left (d x + c\right ) - 288 \, B a^{2} b^{3} \tan \left (d x + c\right )}{48 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.31, size = 268, normalized size = 1.25 \begin {gather*} -\frac {48 \, {\left (C a^{5} - B a^{4} b\right )} d x \cos \left (d x + c\right )^{4} + 3 \, {\left (24 \, C a^{4} b - 32 \, B a^{3} b^{2} - 8 \, C a^{2} b^{3} - 16 \, B a b^{4} - 3 \, C b^{5}\right )} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (24 \, C a^{4} b - 32 \, B a^{3} b^{2} - 8 \, C a^{2} b^{3} - 16 \, B a b^{4} - 3 \, C b^{5}\right )} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (6 \, C b^{5} - 16 \, {\left (3 \, C a^{3} b^{2} - 9 \, B a^{2} b^{3} - 3 \, C a b^{4} - B b^{5}\right )} \cos \left (d x + c\right )^{3} + 3 \, {\left (8 \, C a^{2} b^{3} + 16 \, B a b^{4} + 3 \, C b^{5}\right )} \cos \left (d x + c\right )^{2} + 8 \, {\left (3 \, C a b^{4} + B b^{5}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{48 \, d \cos \left (d x + c\right )^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \int C a^{5}\, dx - \int \left (- B a^{4} b\right )\, dx - \int \left (- B b^{5} \sec ^{4}{\left (c + d x \right )}\right )\, dx - \int \left (- C b^{5} \sec ^{5}{\left (c + d x \right )}\right )\, dx - \int \left (- 4 B a b^{4} \sec ^{3}{\left (c + d x \right )}\right )\, dx - \int \left (- 6 B a^{2} b^{3} \sec ^{2}{\left (c + d x \right )}\right )\, dx - \int \left (- 4 B a^{3} b^{2} \sec {\left (c + d x \right )}\right )\, dx - \int \left (- 3 C a b^{4} \sec ^{4}{\left (c + d x \right )}\right )\, dx - \int \left (- 2 C a^{2} b^{3} \sec ^{3}{\left (c + d x \right )}\right )\, dx - \int 2 C a^{3} b^{2} \sec ^{2}{\left (c + d x \right )}\, dx - \int 3 C a^{4} b \sec {\left (c + d x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 658 vs.
\(2 (205) = 410\).
time = 0.56, size = 658, normalized size = 3.07 \begin {gather*} -\frac {24 \, {\left (C a^{5} - B a^{4} b\right )} {\left (d x + c\right )} + 3 \, {\left (24 \, C a^{4} b - 32 \, B a^{3} b^{2} - 8 \, C a^{2} b^{3} - 16 \, B a b^{4} - 3 \, C b^{5}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (24 \, C a^{4} b - 32 \, B a^{3} b^{2} - 8 \, C a^{2} b^{3} - 16 \, B a b^{4} - 3 \, C b^{5}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (48 \, C a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 144 \, B a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 24 \, C a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 48 \, B a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 72 \, C a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 24 \, B b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 15 \, C b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 144 \, C a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 432 \, B a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 24 \, C a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 48 \, B a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 120 \, C a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 40 \, B b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 9 \, C b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 144 \, C a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 432 \, B a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 24 \, C a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 48 \, B a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 120 \, C a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 40 \, B b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 9 \, C b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 48 \, C a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 144 \, B a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, C a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 48 \, B a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 72 \, C a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, B b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 15 \, C b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{4}}}{24 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 6.70, size = 2500, normalized size = 11.68 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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